(9x-1)/x^2=8

Solution for (9x-1)/x^2=8 equation:

D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(9*x-1)/(x^2) = 8 // - 8

(9*x-1)/(x^2)-8 = 0

(9*x-1)/(x^2)+(-8*x^2)/(x^2) = 0

9*x-8*x^2-1 = 0

9*x-8*x^2-1 = 0

9*x-8*x^2-1 = 0

DELTA = 9^2-(-8*(-1)*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-9)/(-8*2) or x = (-49^(1/2)-9)/(-8*2)

x = 1/8 or x = 1

(x-1/8)*(x-1) = 0

((x-1/8)*(x-1))/(x^2) = 0

((x-1/8)*(x-1))/(x^2) = 0 // * x^2

(x-1/8)*(x-1) = 0

( x-1/8 )

x-1/8 = 0 // + 1/8

x = 1/8

( x-1 )

x-1 = 0 // + 1

x = 1

x in { 1/8, 1 }